M8SCI-9.3

Wave Speed, Frequency & Wavelength

Discover how wave speed depends on the medium, and how frequency and wavelength are connected—with the relationship speed equals frequency times wavelength.

What you'll do in this lesson

A voice-first session with the Crimsora tutor on Wave Speed, Frequency & Wavelength, then targeted practice and FRQs — with the tutor adapting to where you get stuck.

What this lesson covers

Waves behave differently depending on what they travel through. Sound moves at different speeds in air, water, and solid materials—and it cannot travel through a vacuum at all. In this lesson, you'll learn why the medium matters, how frequency and wavelength relate to each other when speed is fixed, and how to use the speed-frequency-wavelength relationship to solve real problems like estimating distance from lightning and thunder.

How the Medium Determines Wave Speed

A wave's speed is a property of the medium it travels in, not of the wave itself. Light travels at about 300,000 kilometers per second in a vacuum, but slows down when it passes through glass or water. Sound behaves the same way: it travels at roughly 340 meters per second in air at room temperature, but about 1,480 meters per second in water, and even faster in steel and other solids. This happens because the material's particles are closer together and pass the vibration along more efficiently.

Crucially, sound does not travel through a vacuum at all. In space, there are no particles to vibrate, so sound has nothing to "ride on." Light, by contrast, can travel through a vacuum. This is why we see light from stars but hear no sound from them.

When a wave stays in the same medium, the speed stays constant. Air remains at 340 m/s as long as temperature and conditions don't change much. This constant speed becomes the key to understanding what happens when frequency or wavelength changes.

The Relationship Between Frequency and Wavelength

Here is the central insight: if wave speed in a medium is constant, then frequency and wavelength must be inversely related. You can think of it this way—imagine a rope vibrating at a certain speed. If you wiggle it faster (higher frequency), the waves stack closer together (shorter wavelength). If you wiggle it slower (lower frequency), the waves stretch out (longer wavelength). The speed of the wave along the rope doesn't change; what changes is how the wave's length relates to how fast you're making it.

This relationship is expressed as:v=f×λv = f \times \lambdawhere vv is wave speed, ff is frequency (measured in hertz, or cycles per second), and λ\lambda is wavelength (measured in meters or another distance unit).

In a given medium, if frequency doubles, wavelength must halve to keep speed the same. If frequency halves, wavelength doubles. This inverse relationship holds for any wave in any medium, as long as the medium doesn't change.

Applying Speed, Distance, and Time to Waves

The relationship v=f×λv = f \times \lambda is one equation connecting wave properties. Another equally important relationship is the everyday distance equation:distance=speed×time\text{distance} = \text{speed} \times \text{time}Or rearranged: time=distancespeed\text{time} = \frac{\text{distance}}{\text{speed}}

You can use this to solve real problems involving sound and light. A classic example is counting the time between a lightning flash and the thunder that follows. Light reaches you almost instantly, but sound lags behind. If you count 3 seconds between the flash and the thunder, and sound travels at 340 m/s in air, then:distance=340 m/s×3 s=1,020 m\text{distance} = 340 \text{ m/s} \times 3 \text{ s} = 1,020 \text{ m}The lightning struck about 1 kilometer away. Another example is sonar: a ship sends a sound pulse into the water, it bounces off the ocean floor and returns. If the total travel time is 2 seconds and sound in water travels at 1,480 m/s, then the ocean floor is at a distance of 1,480×2=2,9601,480 \times 2 = 2,960 meters—but that's the round-trip distance, so you divide by 2 to get the actual depth: 1,480 meters.

Common Misconceptions

One frequent mistake is thinking that frequency determines wave speed. Students sometimes reason, "If I vibrate the rope faster, the wave moves faster." In reality, the wave speed is set by the rope itself—its thickness, tension, and material. Vibrating faster creates a higher-frequency wave, but it stays at the same speed. The wavelength shrinks to accommodate the extra cycles.

Another misconception is confusing the speed of the wave with the speed of the particles in the medium. A sound wave travels at 340 m/s, but the air molecules themselves don't move forward at 340 m/s. They vibrate back and forth by tiny amounts, passing the disturbance along. The disturbance (the wave) propagates at 340 m/s; the particles jiggle much more slowly.

A third pitfall is forgetting that the medium must change for wave speed to change. When solving problems in the same medium (say, sound in air), wave speed is always the same. Only if the wave enters a different material (sound entering water, or light entering glass) does the speed actually shift.

Key terms

Wave speed.
The distance a wave travels per unit time, determined by the properties of the medium it moves through. Measured in meters per second (m/s).
Frequency.
The number of complete vibration cycles a wave makes per second, measured in hertz (Hz). Higher frequency means more cycles in the same time.
Wavelength.
The distance between two consecutive crests (or troughs, or any two matching points) on a wave. Usually measured in meters and represented by the symbol λ\lambda.
Medium.
The material a wave travels through, such as air, water, glass, or a solid rope. Different media have different wave speeds.
Hertz (Hz).
The unit of frequency, equal to one cycle per second. For example, a 60 Hz sound has 60 complete vibrations per second.
Vacuum.
A space with essentially no matter or particles. Sound cannot travel through a vacuum because there are no particles to vibrate.
Sonar.
A technology that sends sound waves through water and listens for echoes to detect objects and measure distances underwater.
Echo.
A reflected sound wave that returns to the source after bouncing off a surface. The time delay tells you the distance to that surface.

Worked example

A ship uses sonar to find the ocean floor. A sound pulse is sent downward and the echo returns after a total of 1.4 seconds. If sound travels at 1,480 meters per second in seawater, how far below the ship is the ocean floor?
Step 1: Identify what we know.

Total round-trip time = 1.4 seconds Speed of sound in seawater = 1,480 m/s

Step 2: Use the distance-speed-time relationship.distance=speed×time\text{distance} = \text{speed} \times \text{time}distance=1,480 m/s×1.4 s=2,072 m\text{distance} = 1,480 \text{ m/s} \times 1.4 \text{ s} = 2,072 \text{ m}Step 3: Correct for round-trip distance.

The sound traveled down to the ocean floor AND back up to the ship. The distance we just calculated is the total distance for that round trip. To find the actual depth, divide by 2:depth=2,072 m2=1,036 m\text{depth} = \frac{2,072 \text{ m}}{2} = 1,036 \text{ m}Step 4: State the answer.

The ocean floor is approximately 1,036 meters (or about 1 kilometer) below the ship.

Practice questions

A sound wave has a frequency of 100 Hz and travels through water at 1,480 m/s. Which of the following is the wavelength of this sound in water?
  1. 14.8 meters
  2. 148 meters
  3. 0.0676 meters
  4. 1,480 meters

Answer: 14.8 meters

Use the relationship v=f×λv = f \times \lambda. Rearranging: λ=vf=1,480 m/s100 Hz=14.8 m\lambda = \frac{v}{f} = \frac{1,480 \text{ m/s}}{100 \text{ Hz}} = 14.8 \text{ m}. A common wrong answer is 148 meters, which results from confusing division with multiplication. Another is 0.0676 meters, which comes from inverting the calculation. The correct answer is 14.8 meters.
A diver is underwater when a friend on the boat bangs two rocks together. The sound reaches the diver very quickly. Explain why sound travels so much faster in water than in air, even though water is denser and should be harder for vibrations to move through.

Answer: Water molecules are much closer together than air molecules, so they can pass vibrations along more efficiently. Even though the medium is denser, the particles are tightly packed and transfer the disturbance quickly from one to the next. In air, the molecules are far apart, so each vibration must travel a greater distance before hitting the next particle. The closeness of water's particles outweighs its density, making sound propagate faster overall.

This question tests understanding of why wave speed depends on the medium's structure. Many students assume denser always means slower vibrations, but the key is how efficiently particles can transfer the disturbance. Water demonstrates that tight molecular spacing is more important than density alone for sound speed.
You see lightning flash and then count 5 seconds before hearing the thunder. Assume sound travels at 340 m/s in air. How far away did the lightning strike? Show your work.

Answer: The distance is 1,700 meters (or 1.7 kilometers). Using distance=speed×time\text{distance} = \text{speed} \times \text{time}, we get distance=340 m/s×5 s=1,700 m\text{distance} = 340 \text{ m/s} \times 5 \text{ s} = 1,700 \text{ m}.

This is a direct application of the distance-speed-time relationship. The light arrives almost instantly, so the 5-second delay is due to sound traveling at a finite speed. A common error is forgetting to multiply (just adding the numbers, or dividing instead). Another is using the speed of light rather than sound, which would give an incorrect answer. The straightforward calculation 340×5=1,700340 \times 5 = 1,700 m is correct.

FAQ

Why does sound not travel through a vacuum?
Sound is a wave that travels by making particles vibrate back and forth. In a vacuum, there are no particles. With nothing to vibrate, the vibration cannot propagate, so sound cannot exist or move through a vacuum. Light, however, is an electromagnetic wave that does not require a medium, so it can travel through empty space.
If I make a rope vibrate twice as fast (double the frequency), what happens to the wavelength?
The wavelength becomes half as long. This is because the wave speed through the rope stays the same—it depends on the rope's material and tension, not on how fast you're wiggling. So if you fit twice as many cycles into the same distance, each cycle must be half as long. The relationship v=f×λv = f \times \lambda ensures that when frequency doubles, wavelength halves.
When sound enters water from air, does its frequency change?
No, frequency does not change. When a wave enters a new medium, the source's vibration rate (frequency) stays the same. However, the wave speed does change in the new medium. Because v=f×λv = f \times \lambda and speed increases while frequency stays constant, the wavelength must increase. This is why sound has a longer wavelength in water than in air, even at the same frequency.
If I use the lightning-thunder method to find distance, why is it important to count the time carefully?
Because distance depends directly on time. The relationship is distance=speed×time\text{distance} = \text{speed} \times \text{time}. Sound speed (340 m/s) is fixed in air. Even a 1-second counting error means a 340-meter error in your distance estimate. If you count 3 seconds instead of 4 seconds, you'll think the lightning was about 340 meters closer than it actually was. Counting carefully and in whole seconds gives the best accuracy.

Learn this with a teacher, not a page

The Crimsora tutor teaches Wave Speed, Frequency & Wavelength live — explaining on a whiteboard, asking you questions, and adapting to where you get stuck.