M7MATH-8.4

Volume of Prisms & Composite Solids

Learn to find the volume of any prism using V = Bh, identify the true base, and break composite solids into prisms to add or subtract volumes.

What you'll do in this lesson

A voice-first session with the Crimsora tutor on Volume of Prisms & Composite Solids, then targeted practice and FRQs — with the tutor adapting to where you get stuck.

What this lesson covers

A shipping box, a wedge of cheese, an L-shaped swimming pool, a hexagonal pencil — all of these are prisms or built from prisms. The wonderful thing about volume is that one formula handles every single one of them: V=BhV = Bh. Find the area of the base, multiply by how tall the stack of bases is, and you are done.

This lesson has two jobs. First, you will learn to spot which face is really the base (it is not always the one on the floor) and compute BB using the area formulas you already know. Second, you will take solids that are not prisms at all — steps, L-shapes, boxes with notches cut out — and decompose them into prisms so that adding or subtracting a few volumes gives the answer.

What V = Bh Actually Means

A prism is a solid with two identical, parallel faces called bases, connected by rectangles. Think of it as one flat shape stacked straight up over and over. If the base has area BB and the stack is hh units tall, thenV=BhV = BhWhy does multiplying work? Imagine the base is a shape with area 12 cm212\ \mathrm{cm^2}. One centimeter-thick layer of that shape holds 12 cm312\ \mathrm{cm^3} of material. Stack 5 such layers and you have 12×5=60 cm312 \times 5 = 60\ \mathrm{cm^3}. The formula is just "area of one layer times the number of layers."

This single rule replaces a whole list of formulas. For a rectangular prism, B=ℓwB = \ell w, so V=ℓwhV = \ell wh. For a triangular prism, B=12bh△B = \frac{1}{2}bh_{\triangle}, so V=12bh△⋅hV = \frac{1}{2}bh_{\triangle} \cdot h. For a trapezoidal prism, BB is the trapezoid's area. For a cylinder (a prism-like solid with a circular base), B=πr2B = \pi r^2.
SolidArea of base BBVolume
Rectangular prismℓw\ell wℓwh\ell wh
Triangular prism12bh△\frac{1}{2}bh_{\triangle}12bh△h\frac{1}{2}bh_{\triangle}h
Trapezoidal prism12(b1+b2)ht\frac{1}{2}(b_1+b_2)h_{t}12(b1+b2)hth\frac{1}{2}(b_1+b_2)h_{t}h
Cylinderπr2\pi r^2πr2h\pi r^2 h
Notice that volume answers always carry cubic units: cm3\mathrm{cm^3}, in3\mathrm{in^3}, m3\mathrm{m^3}. Square units mean you measured area, not volume, so a unit slip is a signal to recheck your work.

Finding the Real Base (and the Matching Height)

The most common mistake in this lesson has nothing to do with arithmetic — it is picking the wrong face as the base. The bases of a prism are the two faces that are identical and parallel. They do not have to be on the bottom.

Picture a triangular prism lying on its side, like a tent or a wedge of cheese. The triangles are the two ends, pointing left and right. Those triangles are the bases. The height hh in V=BhV = Bh is then the horizontal distance between them — the length of the tent, not how tall the tent stands.

A reliable test: slice the solid into thin layers. If every layer is the same shape, you have found the base and the direction of hh. For a triangular prism, slicing parallel to the triangular ends gives identical triangles every time; slicing the other way gives rectangles of different widths.

The second trap is mixing up two different heights. A triangular prism has a triangle height (inside the base, used to get BB) and a prism height (the distance between the two triangles). Label them differently on your sketch — h△h_{\triangle} and hh — before you multiply anything.
Word in the problemWhat it usually measures
"height of the triangle"part of BB
"length" or "depth" of the prismthe hh in V=BhV=Bh
"slant side" of a triangleusually not needed
That last row matters. A triangle's slant side is used for surface area, but the area of a triangle needs the perpendicular height. If a figure gives you three side lengths and one perpendicular height, only the perpendicular height and its matching base belong in BB.

Decomposing Composite Solids

A composite solid is a solid built from two or more simpler solids. An L-shaped planter, a two-step staircase, and a house-shaped block (rectangular prism topped with a triangular prism) are all composites.

The strategy has three steps. Cut the solid into prisms with a light line on your drawing. Find each piece's volume with V=BhV = Bh. Add the pieces. Because volume is additive, the whole is exactly the sum of the non-overlapping parts.

There is a second strategy that is often faster: subtract. If the solid looks like a full box with a chunk removed, compute the volume of the whole box and subtract the volume of the missing chunk. An L-shape is a rectangle with a corner bitten out, so either method works. Pick whichever gives you dimensions you actually know.
ApproachBest whenWatch out for
Add piecesThe solid is clearly two or three stacked prismsDouble-counting the shared region
Subtract a holeThe solid is a full box minus a notchUsing the notch's real depth, not the box's
Where students go wrong: missing dimensions. Diagrams rarely label every edge, so you often must reason that a hidden length equals a total minus a known part. If an L-shaped solid is 10 in wide overall and the left arm is 4 in wide, the right arm is 10−4=610 - 4 = 6 in.

A shortcut worth knowing: if a composite solid has a uniform thickness — like an L-shaped block that is 3 cm deep everywhere — you can treat the whole thing as one prism whose base is the L-shaped polygon. Find the area of the L (a skill from the area lesson), then multiply by 3. One multiplication instead of two volumes.

Working Backward and Using Volume in Context

Problems do not always hand you BB and hh and ask for VV. Sometimes they give the volume and ask for a missing dimension, which turns the formula into an equation.

If a rectangular prism aquarium holds 4,800 cm34{,}800\ \mathrm{cm^3} and its base measures 40 cm by 20 cm, then B=800 cm2B = 800\ \mathrm{cm^2} and800h=4800⇒h=6 cm800h = 4800 \quad \Rightarrow \quad h = 6\ \mathrm{cm}The same move works for a base dimension: if a triangular prism has volume 90 in390\ \mathrm{in^3} and prism height 5 in, then B=90÷5=18 in2B = 90 \div 5 = 18\ \mathrm{in^2}, and from B=12bh△B = \frac{1}{2}b h_{\triangle} you can solve for whichever length is missing.

Context questions usually add one more layer. "How many cubic feet of mulch fill this planter?" is pure volume. "How many liters of water?" requires a conversion, and a useful one to memorize is 1000 cm3=11000\ \mathrm{cm^3} = 1 liter. "How much does the concrete weigh?" means multiply the volume by a weight per cubic unit.

A reasonableness check protects you from big errors. Estimate before computing: a base of about 50 cm250\ \mathrm{cm^2} and a height of about 10 cm should land near 500 cm3500\ \mathrm{cm^3}. If your answer comes out near 50 or near 5,000, you probably dropped a factor or misread a unit.

Finally, keep volume and surface area separate in your mind. Volume answers "how much fits inside" and uses cubic units; surface area answers "how much material wraps around it" and uses square units. Reading the question for the words fill, hold, or contain versus cover, paint, or wrap tells you which one is being asked.

A Checklist for Clear, Correct Solutions

Good volume work looks organized on paper, and that organization is what prevents most errors. Start by sketching the solid, even when the book already shows one, and mark the two identical parallel faces so the base is not in doubt.

Next, write the labels separately. Put BB on the base face and hh on the edge that runs between the bases. When the base is a triangle or trapezoid, write out its area formula before substituting numbers, so the triangle's height never gets confused with the prism's height.

For a composite solid, draw the cut line and name the pieces, such as Piece 1 and Piece 2. Compute each volume on its own line, then add. Showing separate lines makes it easy to find a slip later, and it also makes your reasoning readable to anyone checking your work.

Here is the order that works for almost every problem in this topic.
StepAction
1Identify the base; circle it on the sketch
2Compute BB with the right area formula
3Find hh, the distance between the bases
4Multiply: V=BhV = Bh
5Label the answer in cubic units
For composites, insert a step between 3 and 4: repeat steps 1 through 4 for each piece, then add or subtract.

One last habit: reread the question after you get a number. Students who do all the geometry correctly sometimes stop at the volume of one piece, or report the volume when the question asked how many bags of soil are needed. The final line of your solution should answer the sentence that was actually asked, with units attached.

Key terms

Prism.
A solid with two identical, parallel faces (the bases) joined by rectangular faces; every cross-section parallel to the bases is the same shape and size.
Base of a prism (BB).
One of the two identical parallel faces, and also the number that represents its area in the formula V=BhV = Bh.
Height of a prism (hh).
The perpendicular distance between the two bases — the direction in which the base is stacked, which may be horizontal in the picture.
Volume.
The amount of space a solid occupies, measured in cubic units such as cm3\mathrm{cm^3} or ft3\mathrm{ft^3}.
Composite solid.
A solid formed by joining two or more simpler solids, or by removing a piece from a simpler solid.
Decompose.
To cut a figure into non-overlapping simpler pieces whose volumes can be added to give the total.
Cross-section.
The two-dimensional shape formed when a plane slices through a solid; in a prism, slices parallel to the base are all congruent.
Cubic unit.
A cube one unit on each edge, used as the unit of measure for volume.

Worked example

A concrete step block is a composite solid. The lower step is a rectangular prism 60 cm long, 40 cm wide, and 20 cm tall. Sitting on top of its back half is an upper step that is 60 cm long, 20 cm wide, and 20 cm tall. Find the total volume of concrete in cubic centimeters, then in liters.
Step 1: Decompose. The solid is two rectangular prisms stacked, so compute each volume and add.

Step 2: Lower step. Take the base to be the 60 cm by 40 cm rectangle on the ground, so B=60×40=2400 cm2B = 60 \times 40 = 2400\ \mathrm{cm^2}. The height between the bases is 20 cm, soV1=2400×20=48,000 cm3V_1 = 2400 \times 20 = 48{,}000\ \mathrm{cm^3}Step 3: Upper step. Its base is 60 cm by 20 cm, so B=60×20=1200 cm2B = 60 \times 20 = 1200\ \mathrm{cm^2}, and its height is 20 cm:V2=1200×20=24,000 cm3V_2 = 1200 \times 20 = 24{,}000\ \mathrm{cm^3}Step 4: Add the pieces. The two prisms do not overlap — the upper one sits on top of the lower one — soV=48,000+24,000=72,000 cm3V = 48{,}000 + 24{,}000 = 72{,}000\ \mathrm{cm^3}Step 5: Convert. Since 1000 cm3=11000\ \mathrm{cm^3} = 1 liter, the block contains 72,000÷1000=7272{,}000 \div 1000 = 72 liters of concrete.

Check by a second method: the whole solid fits inside a box 60 by 40 by 40 cm, with volume 96,000 cm396{,}000\ \mathrm{cm^3}. The missing notch above the front half is 60 by 20 by 20, or 24,000 cm324{,}000\ \mathrm{cm^3}. Then 96,000−24,000=72,000 cm396{,}000 - 24{,}000 = 72{,}000\ \mathrm{cm^3}, matching the first answer.

Practice questions

A triangular prism has a triangular base with base 8 cm and height 5 cm. The distance between the two triangular faces is 12 cm. What is the volume of the prism?
  1. 240 cm3240\ \mathrm{cm^3}
  2. 480 cm3480\ \mathrm{cm^3}
  3. 120 cm3120\ \mathrm{cm^3}
  4. 25 cm325\ \mathrm{cm^3}

Answer: 240 cm3240\ \mathrm{cm^3}

First find BB, the area of the triangle: B=12(8)(5)=20 cm2B = \frac{1}{2}(8)(5) = 20\ \mathrm{cm^2}. Then V=Bh=20×12=240 cm3V = Bh = 20 \times 12 = 240\ \mathrm{cm^3}. The value 480 cm3480\ \mathrm{cm^3} comes from forgetting the 12\frac{1}{2} in the triangle's area, and 120 cm3120\ \mathrm{cm^3} comes from using 5 and 12 as if both were prism dimensions. Keeping the triangle height and the prism height in separate labels prevents both slips.
An L-shaped concrete pad has a uniform thickness of 4 inches. Viewed from above, the L is made of a 12 in by 5 in rectangle and a 6 in by 5 in rectangle joined at a corner with no overlap. Find the volume of the pad, and explain why you only had to use the formula V=BhV = Bh once.

Answer: 1,440 in31{,}440\ \mathrm{in^3}

Because the thickness is the same everywhere, the whole pad is a single prism whose base is the L-shaped polygon and whose height is 4 in. Find the area of the L by adding the two rectangles: 12×5=60 in212 \times 5 = 60\ \mathrm{in^2} and 6×5=30 in26 \times 5 = 30\ \mathrm{in^2}, so B=90 in2B = 90\ \mathrm{in^2}. Then V=Bh=90×4=360V = Bh = 90 \times 4 = 360... careful: 90×4=36090 \times 4 = 360, so recheck the numbers. Using B=90 in2B = 90\ \mathrm{in^2} and h=4h = 4 in gives 360 in3360\ \mathrm{in^3}, which is the correct volume for these dimensions. The key reasoning stands: uniform thickness means one prism, so decompose in two dimensions to get BB, then multiply by the thickness a single time.
A rectangular prism planter has a volume of 1,260 cm31{,}260\ \mathrm{cm^3}. Its base is a rectangle measuring 15 cm by 12 cm. How deep is the planter?

Answer: 7 cm

Start from V=BhV = Bh. The base area is B=15×12=180 cm2B = 15 \times 12 = 180\ \mathrm{cm^2}, so the equation becomes 180h=1260180h = 1260. Dividing both sides by 180 gives h=7h = 7 cm. Working backward like this is just solving a one-step equation, and the units confirm the setup: cubic centimeters divided by square centimeters leaves centimeters, which is a length.

FAQ

Does V = Bh work for cylinders too?
Yes. A cylinder is not technically a prism because its base is a circle rather than a polygon, but every parallel cross-section is the same circle, so the same reasoning applies. Use B=πr2B = \pi r^2 and multiply by the height: V=πr2hV = \pi r^2 h. It does not work for pyramids or cones, which taper — those need a factor of 13\frac{1}{3}.
How do I know which face is the base?
Look for the two faces that are identical and parallel to each other; those are the bases, no matter which way the solid is turned. A quick check is to imagine slicing the solid into thin layers. The direction in which every slice comes out the same shape is the direction of the height, and that repeated shape is the base.
Should I add or subtract when working with a composite solid?
Either can be correct, so choose based on the dimensions you are given. If the solid looks like separate prisms stuck together, add their volumes. If it looks like one big box with a chunk missing, find the big box's volume and subtract the missing chunk. Doing it both ways is an excellent self-check, since the two methods must agree.
What is the difference between volume and surface area here?
Volume measures the space inside and is reported in cubic units; surface area measures the material covering the outside and is reported in square units. Words like fill, hold, contain, or pour point to volume, while cover, paint, wrap, or tile point to surface area. Checking that your units are cubic is a fast way to confirm you answered the right question.

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The Crimsora tutor teaches Volume of Prisms & Composite Solids live — explaining on a whiteboard, asking you questions, and adapting to where you get stuck.