ALG1-1.3

Simplifying Expressions: Distributive Property & Like Terms

Learn to simplify algebra expressions with the distributive property (including negative multipliers) and combining like terms, with worked steps and common error fixes.

What you'll do in this lesson

A voice-first session with the Crimsora tutor on Simplifying Expressions: Distributive Property & Like Terms, then targeted practice and FRQs — with the tutor adapting to where you get stuck.

What this lesson covers

You have already evaluated expressions and translated words into algebra. Now you will rewrite expressions so they are shorter and easier to work with — without changing their value. That is what "simplify" means: 3(x+4)2x3(x+4)-2x and x+12x+12 look different, but plug in any number for xx and they produce the same output every single time.

Two tools do almost all of the work: the distributive property, which clears parentheses, and combining like terms, which collects the pieces that match. The hard part is not the idea — it is the bookkeeping, especially when a negative sits in front of a parenthesis. This guide walks through the structure of a term, the mechanics of distributing, the rule for what counts as "like," and the specific places where careful students still slip up.

Terms, Coefficients, and What "Simplify" Really Means

An algebraic expression is built from terms — chunks separated by plus or minus signs. In 7x24x+97x^2 - 4x + 9, the terms are 7x27x^2, 4x-4x, and 99. Notice that the sign in front belongs to the term. Reading 4x-4x as a negative term (instead of "minus four x") saves enormous trouble later.

Each term has a coefficient (the number multiplying the variable part) and a variable part (the letters with their exponents). In 4x-4x, the coefficient is 4-4 and the variable part is xx. A term like xx has an invisible coefficient of 11; x-x has coefficient 1-1. A term with no variable at all, like 99, is a constant.

To simplify means to write an equivalent expression with as few terms as possible and no unnecessary parentheses. Equivalent is the key word: the two expressions must give identical values for every replacement of the variable. Simplifying is not solving — there is no equals sign and no answer like x=5x = 5. Your result is another expression.
ExpressionNumber of termsCoefficients
5x+35x + 3255, and the constant 33
x2+7x2-x^2 + 7x - 231-1, 77, and the constant 2-2
6(x4)6(x - 4)1 (a product)66 times a two-term factor
That last row matters. 6(x4)6(x-4) is a single term until you distribute, because multiplication holds it together. Recognizing structure — is this a sum of terms, or a product? — tells you which tool to reach for first.

The Distributive Property, Including Negative Multipliers

The distributive property says a(b+c)=ab+aca(b + c) = ab + ac. The outside factor multiplies every term inside, not just the first one. It also works with subtraction: a(bc)=abaca(b - c) = ab - ac, since subtracting is adding the opposite.4(3x+5)=43x+45=12x+204(3x + 5) = 4 \cdot 3x + 4 \cdot 5 = 12x + 20Negative multipliers are where most errors live. When the factor outside is negative, every sign inside flips:2(5x7)=(2)(5x)+(2)(7)=10x+14-2(5x - 7) = (-2)(5x) + (-2)(-7) = -10x + 14Students very often write 10x14-10x - 14 here, forgetting that negative times negative is positive. Slow down and multiply the signs deliberately, term by term.

A subtler case is a bare minus sign in front of parentheses, as in 9(4x3)9 - (4x - 3). There is no visible number, but the minus sign means 1-1 is the multiplier:91(4x3)=94x+3=124x9 - 1(4x - 3) = 9 - 4x + 3 = 12 - 4xWriting the invisible 1-1 explicitly, every time, is the single best habit for this lesson.
SetupDistributedFrequent wrong answer
3(x+6)3(x + 6)3x+183x + 183x+63x + 6 (forgot second term)
5(x+2)-5(x + 2)5x10-5x - 105x+10-5x + 10
4(x3)-4(x - 3)4x+12-4x + 124x12-4x - 12
(2x9)-(2x - 9)2x+9-2x + 92x9-2x - 9
The property runs both directions. 12x+2012x + 20 can be rewritten as 4(3x+5)4(3x + 5) by pulling out the common factor 44. That reverse move is factoring, and you will lean on it heavily in later units.

Combining Like Terms

Like terms have exactly the same variable part — same letters, same exponents. Only their coefficients may differ. 3x3x and 8x-8x are like terms. 3x3x and 3x23x^2 are not, because xx and x2x^2 are different variable parts. 5xy5xy and 2yx2yx are like terms, since multiplication can be reordered and both have variable part xyxy.

To combine, add the coefficients and keep the variable part unchanged:3x8x=(38)x=5x3x - 8x = (3 - 8)x = -5xWhy does this work? The distributive property again, read backwards: 3x8x=(38)x3x - 8x = (3-8)x. Combining like terms is not a separate rule; it is factoring out the shared variable.

A classic misconception is changing the exponent: x2+x2x^2 + x^2 is 2x22x^2, not x4x^4. You are counting how many x2x^2 blocks you have, not multiplying them. Similarly, 4x+34x + 3 cannot be combined into 7x7x — three ones and four x's are different kinds of objects, and if you test x=2x = 2 you get 1111 versus 1414, which proves they are not equivalent.

A reliable procedure: after distributing, underline or circle each family of like terms with a different mark, dragging the sign in front along with each term. Then add each family separately.6x4+2x+9    (6x+2x)+(4+9)    8x+56x - 4 + 2x + 9 \;\to\; (6x + 2x) + (-4 + 9) \;\to\; 8x + 5By convention, write the result in descending order of exponent with the constant last: 8x+58x + 5, not 5+8x5 + 8x. Both are correct, but the standard order makes later work easier to read.

Multi-Step Simplification and Where Answers Go Wrong

Most problems in this lesson mix both tools. The order is nearly always the same: clear the innermost parentheses by distributing, then combine like terms, then write the terms in standard order.

Consider 83(2x5)+7x8 - 3(2x - 5) + 7x. A very common wrong first move is subtracting 33 from 88 to get 5(2x5)5(2x-5). That violates the order of operations — the 33 is attached to the parentheses by multiplication, so it must distribute before anything else touches it. Distribute first: 86x+15+7x8 - 6x + 15 + 7x, then combine: x+23x + 23.

Nested parentheses work from the inside out. In 2[3x+4(x1)]2[3x + 4(x - 1)], handle 4(x1)=4x44(x-1) = 4x - 4 first, giving 2[3x+4x4]=2[7x4]=14x82[3x + 4x - 4] = 2[7x - 4] = 14x - 8.
StepWhat you doWatch for
1Distribute every factor over its parenthesesNegative multipliers; invisible 1-1
2Rewrite as a plain sum of termsKeep each sign attached to its term
3Group like termsxx and x2x^2 are not alike
4Add coefficientsVariable part never changes
5Write in descending orderConstant goes last
To check your work, pick a value like x=3x = 3, evaluate the original expression and your simplified one, and compare. If they disagree, an error is hiding somewhere — usually a dropped negative. This substitution check catches almost every mistake in under a minute and is worth doing on any problem you are unsure about.

Key terms

Term.
A single number, variable, or product of numbers and variables, separated from other terms by plus or minus signs. The sign in front belongs to the term.
Coefficient.
The numerical factor of a term. In 7y-7y the coefficient is 7-7; in xx it is 11.
Constant.
A term with no variable, such as 99 or 4-4. Its value never changes.
Like terms.
Terms with identical variable parts, including identical exponents, such as 5x25x^2 and 2x2-2x^2. Only like terms may be combined.
Distributive property.
The rule a(b+c)=ab+aca(b+c) = ab + ac, which lets you multiply an outside factor by every term inside parentheses.
Equivalent expressions.
Two expressions that produce the same value for every allowed replacement of the variable, such as 3(x+2)3(x+2) and 3x+63x+6.
Simplify.
To rewrite an expression in an equivalent form with no unnecessary parentheses and the fewest possible terms.
Factoring out.
Reversing distribution by pulling a common factor to the outside, as in 12x+20=4(3x+5)12x + 20 = 4(3x+5).

Worked example

Simplify completely: 5(2x3)2(4x7)+3x5(2x - 3) - 2(4x - 7) + 3x
Step 1 — Distribute the first factor. Multiply 55 by each term inside: 52x=10x5 \cdot 2x = 10x and 5(3)=155 \cdot (-3) = -15. So 5(2x3)=10x155(2x-3) = 10x - 15.

Step 2 — Distribute the second factor, sign included. The multiplier here is 2-2, not 22. Multiply: (2)(4x)=8x(-2)(4x) = -8x and (2)(7)=+14(-2)(-7) = +14. So 2(4x7)=8x+14-2(4x-7) = -8x + 14. The most common slip is writing 14-14; negative times negative is positive.

Step 3 — Rewrite the whole expression as a sum of terms.10x158x+14+3x10x - 15 - 8x + 14 + 3xStep 4 — Group like terms. The xx terms are 10x10x, 8x-8x, and 3x3x. The constants are 15-15 and 1414.(10x8x+3x)+(15+14)(10x - 8x + 3x) + (-15 + 14)Step 5 — Add the coefficients in each group. For the variable terms: 108+3=510 - 8 + 3 = 5, giving 5x5x. For the constants: 15+14=1-15 + 14 = -1.5x15x - 1Step 6 — Check by substitution. Let x=2x = 2. Original: 5(43)2(87)+6=5(1)2(1)+6=52+6=95(4-3) - 2(8-7) + 6 = 5(1) - 2(1) + 6 = 5 - 2 + 6 = 9. Simplified: 5(2)1=95(2) - 1 = 9. They match, so 5x15x - 1 is correct.

Practice questions

Simplify 3(2x5)+4x-3(2x - 5) + 4x.
  1. 2x+15-2x + 15
  2. 2x15-2x - 15
  3. 10x+15-10x + 15
  4. 2x+5-2x + 5

Answer: 2x+15-2x + 15

Distribute 3-3 across both terms: (3)(2x)=6x(-3)(2x) = -6x and (3)(5)=+15(-3)(-5) = +15, giving 6x+15+4x-6x + 15 + 4x. Combine the xx terms: 6x+4x=2x-6x + 4x = -2x. The result is 2x+15-2x + 15. The answer 2x15-2x - 15 comes from forgetting that a negative times a negative is positive, and 10x+15-10x + 15 comes from combining 6x-6x with 4x4x incorrectly as though the signs were both negative.
A student simplified 12(5x8)12 - (5x - 8) and got 45x4 - 5x. Explain the mistake and give the correct simplified expression.

Answer: The correct answer is 205x20 - 5x (equivalently 5x+20-5x + 20). The student distributed the minus sign only to the first term inside the parentheses.

The minus sign in front of the parentheses means multiply by 1-1: 121(5x8)=125x+812 - 1(5x - 8) = 12 - 5x + 8. Both terms inside change sign, so 8-8 becomes +8+8. Combining constants gives 12+8=2012 + 8 = 20, so the expression simplifies to 205x20 - 5x. The student's version, 45x4 - 5x, came from computing 12812 - 8, which treats the 8-8 as if it stayed negative. A quick check with x=0x = 0 settles it: the original is 12(8)=2012 - (-8) = 20, matching 205x20 - 5x, not 44.
Simplify 4(3y+2)(y6)+y24(3y + 2) - (y - 6) + y^2 and state how many terms your answer has.

Answer: y2+11y+14y^2 + 11y + 14, which has three terms.

Distribute the 44: 12y+812y + 8. Distribute the invisible 1-1: y+6-y + 6. The expression becomes 12y+8y+6+y212y + 8 - y + 6 + y^2. Combine the yy terms: 12yy=11y12y - y = 11y (remember y-y has coefficient 1-1). Combine constants: 8+6=148 + 6 = 14. The y2y^2 term has no partner, since y2y^2 and yy are not like terms. Written in descending order of exponent, the answer is y2+11y+14y^2 + 11y + 14 — three terms.

FAQ

Are 3x3x and 3x23x^2 like terms?
No. Like terms must match in both the variable and the exponent. 3x3x counts groups of xx, while 3x23x^2 counts groups of xxx \cdot x, so they cannot be added into one term. You can verify this: at x=4x = 4, 3x=123x = 12 but 3x2=483x^2 = 48. The expression 3x+3x23x + 3x^2 is already simplified.
Why do all the signs flip when I subtract a parenthesis?
Because a bare minus sign in front of parentheses is really a multiplier of 1-1, and that 1-1 distributes to every term inside. So (2x9)-(2x - 9) becomes (1)(2x)+(1)(9)=2x+9(-1)(2x) + (-1)(-9) = -2x + 9. Writing the 1-1 in explicitly before you distribute prevents the most common error in this lesson.
Do I always have to distribute first?
Distribute before combining anything that sits outside the parentheses with something inside — that part is required by the order of operations. But if the terms inside the parentheses are themselves like terms, you may simplify inside first. In 3(2x+5x)3(2x + 5x), you can combine to get 3(7x)=21x3(7x) = 21x, or distribute to get 6x+15x=21x6x + 15x = 21x. Both routes give the same result.
How do I know my simplified expression is correct?
Substitute a convenient number for the variable — x=2x = 2 or x=3x = 3 works well, but avoid x=0x = 0 and x=1x = 1 since they can hide sign errors — and evaluate both the original expression and your answer. Equivalent expressions must give the same value. If the two values differ, retrace your distribution step first; a dropped negative is the usual cause.

Learn this with a teacher, not a page

The Crimsora tutor teaches Simplifying Expressions: Distributive Property & Like Terms live — explaining on a whiteboard, asking you questions, and adapting to where you get stuck.